السلام عليكم ورحمة الله تعالئ وبركاته- استخدام المعادلة الصفرية
طبعا قديما تعلم الجميع من بعضهم البعض بعدة طرق منها التجارة كطريق احببت ان اضع هذا الاستخدام للمعادلة الصفرية لتثبت الهرم الحقيقي مما يعني ان الاهرامات التئ بنيت خاطئة وتم تعميت الحقيقة فيها وكان الغرض منها بث الرعب والجهل وفقط
تقبلوا خالص تحياتي :)
33-43=0=2=10
(3.3-4.3)*10=0=2=10
(-1))*10=0=2=10
-1*10=0*0=2*0=10*0
0=-1^0 =2=10^0
3t-4t=-1
3t-44=-1
3t=43
t=43/3
4t-60
3t-4t=-1
3t-4(43/3)=-1
3t=4(43/3)-1
3t=4t-1
t=1
t=1=43/3 =7/3
t=1=7/3 =7-3=4 =t
0=2=10=t3-4t =34-44=10
t=4=43/3=1 =43-3=40 =4
t=4
t=1
t3-4t=31-44 in m 3-16=-13 =-4
t3-4t=31-44in a 4-8=-4
-4=0
0=2=10=-4=4 =-1
t=1=4
0 2 10 -4 4 -1
1 4
001000111 = 1797+326+5100-3400=3523 =1101 t101
1=t101 =t =4
t101=4 =101*1 =101
t=101 =123 =6 =0101
0101=101
1+4=tt 01010101=-3400+326-3400+326=-6148 =-1*6148=0*0100 =0+0100 = 100
tt=100
t=1=4 ,tt=100 4+4=8 =2rr =00101
tt=00101 = 32=010 =10
tt=10 = 100
t=1=4
0=2=10=t3-4t=-4=4
t=0
t=t3-4t
t=t3-4t
t=0=2=10=-4=4=-1=1 =43/3=7/3=7-3=4=101
t3-4t=t 101*3-4*t=t
101+3-4+t=t
101+01-101+101=t
111-000=t
t=111
4+t=5
101+111=5 =1011 =001 =01
5=3=01 =21=11+10=11t
11t=5=3=44=-44=11=-11
dimisions 5 3 -44 44 11 -11
5+3=8 -44+44 =0 11-11=0
8 0 0 = 2rr=00101 =101
so we have a one molecule that is 101 its is an even molecule that have 05 03 -044 044 -011 011 as diminsions in space
05 03 -044 044 -011 011
-44 44 in x axis -11 11 in y axis 5 3 موازية لاحد المستويان
this gives us pyrmid or molecule 101
charactristica of molecule 101 t3=4t t01=101t then t=1
so when we are in status where t=1 we get molecule 101
that shows why things fluctuate between highs and lows .
cheers :)
when movement complete we get 101
move is in three dimisions end result always is 101 which is 05 03 -044 044 -011 011 move .
t3-4t=0 10101-1001 =0 1001 = 22= 00 =0
when t =101 0=0
0=2
t=2 = 11 =011 = 31
t3-4t=31 10101-4t=31
4t=31-10101
4t=011-10101 =0101
t=0101 - 101 =1111 =04=4
when 0 = 2 then t =4
0=1
t=1 = 01 = 3
t3-4t=3 10101-4t=3
4t=001-010101=001
t=001-101= 001 =21 = 3
when 0 = 1 t = 3
0=-1 t=-1 = 10 = 010 = 21
t3-4t=3 10101-4t=21
4t=001-10101=001
t =001-101=001 =21=3
when 0 = -1 t = 3 =001
4001 = 0013 - 101
101001= 00101 - 101
101001+00101=101
1001 = 101
11=101
t=4
03 03 -01 01 -021 021
03 03 -01 01 -021 021 when we have 001 molecule
when 0=-1 = 010 t = 3 = 001 we have molecule 001 which is 03 02 -01 01 -021 021 in dimensions
3=-1
when 0 = 2
t=11 =011 = 3+1 = 4
t3-4t=4
4t=4 - 3t
4t=011-3101
011t =011 -01101
t=01101 = 32 = 010 =5
when 0 = 2 t = 5
0=2 t =5 =010 = 21
t3-4t=3 10101-4t=21
4t=001-10101=001
t =001-101=001 =21=3
when 0 = 2 t = 5 =010
4010 = 0013 - 101
101010= 00101 - 101
101010+00101=101
1001 = 101
11=101
t=2
05 03 -02 02 -021 021 when we have molecule 010
0=4 = 101 =0101 = 22=4
when 0=4 t = 4 =0101 = 101 =2+1 = 3
t3-4t=3
4t=3-t3
4t=101-10101
101t=101-10101
t=-10101 =101010 = 33=6 = 0101
when 0=4 t =4
t3-4t=0 6*3-4*6 =6
03 06 -04 04 -06 06 when we have molecule 0101 = 101
so we have three molecules 101 001 and 010 as basic of structure
any diferent molecule is fluctuating end structure
we have basic building structures and logical alterneted fluctuating moves with logical zeroism alternated possibilities by any new added zero value
zero value depends on move and external rebalancing physical effects .
